{"id":1722,"date":"2026-08-13T09:00:30","date_gmt":"2026-08-13T12:00:30","guid":{"rendered":"https:\/\/www.aprovaconcursos.com.br\/blog\/?p=1722"},"modified":"2026-08-13T10:07:32","modified_gmt":"2026-08-13T13:07:32","slug":"equacao-do-1-grau","status":"publish","type":"post","link":"https:\/\/www.aprovaconcursos.com.br\/blog\/equacao-do-1-grau\/","title":{"rendered":"Equa\u00e7\u00e3o do 1\u00ba Grau: como isolar o &#8220;x&#8221; sem errar na prova"},"content":{"rendered":"<figure id=\"attachment_1728\" aria-describedby=\"caption-attachment-1728\" style=\"width: 1200px\" class=\"wp-caption alignnone\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-1728 size-full\" src=\"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/08\/equacao-do-1-grau-para-concursos.webp\" alt=\"Equa\u00e7\u00e3o do 1\u00ba Grau: como n\u00e3o errar na prova\" width=\"1200\" height=\"628\" srcset=\"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/08\/equacao-do-1-grau-para-concursos.webp 1200w, https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/08\/equacao-do-1-grau-para-concursos-300x157.webp 300w, https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/08\/equacao-do-1-grau-para-concursos-1024x536.webp 1024w, https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/08\/equacao-do-1-grau-para-concursos-768x402.webp 768w\" sizes=\"auto, (max-width: 1200px) 100vw, 1200px\" \/><figcaption id=\"caption-attachment-1728\" class=\"wp-caption-text\">Equa\u00e7\u00e3o do 1\u00ba Grau.<\/figcaption><\/figure>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"3:1-3:405;60-464\">Se voc\u00ea est\u00e1 firme na caminhada dos estudos para concursos p\u00fablicos, saiba que a <strong>Equa\u00e7\u00e3o do 1\u00ba Grau<\/strong> \u00e9 a linguagem essencial da Matem\u00e1tica e do Racioc\u00ednio L\u00f3gico. Ela n\u00e3o aparece apenas em quest\u00f5es diretas pedindo para resolver uma igualdade. Ela \u00e9 a ferramenta central utilizada pelas bancas para traduzir problemas de idades, fra\u00e7\u00f5es de quantidades, or\u00e7amentos e misturas para a linguagem alg\u00e9brica.<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"5:1-5:389;466-854\">A boa not\u00edcia \u00e9 que resolver uma equa\u00e7\u00e3o do primeiro grau n\u00e3o exige nenhum tipo de malabarismo. O segredo est\u00e1 em respeitar a fundamenta\u00e7\u00e3o conceitual das opera\u00e7\u00f5es inversas e manter a organiza\u00e7\u00e3o do rascunho do in\u00edcio ao fim. No entanto, na hora da prova, o estresse e a pressa com o tempo fazem muitos candidatos escorregarem na interpreta\u00e7\u00e3o dos enunciados ou cometerem erros de sinal.<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"7:1-7:227;856-1082\">Neste artigo, vamos trabalhar a l\u00f3gica por tr\u00e1s da equa\u00e7\u00e3o do 1\u00ba grau, o passo a passo para isolar a inc\u00f3gnita <em>x<\/em> com total rigor matem\u00e1tico e as melhores estrat\u00e9gias para voc\u00ea n\u00e3o cair nas pegadinhas das bancas examinadoras.<\/p>\n<h2 class=\"mt-3 -mb-1 text-[1.125rem] font-bold\" dir=\"ltr\" data-sourcepos=\"9:1-9:59;1084-1142\">O conceito fundamental: o que \u00e9 uma Equa\u00e7\u00e3o do 1\u00ba Grau?<\/h2>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"11:1-11:83;1144-1226\">Antes de sair realizando opera\u00e7\u00f5es, precisamos entender o significado do conceito.<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"13:1-13:315;1228-1542\">Uma equa\u00e7\u00e3o \u00e9 uma senten\u00e7a matem\u00e1tica aberta expressa por uma igualdade que envolve uma ou mais letras chamadas de inc\u00f3gnitas. Ela \u00e9 denominada de 1\u00ba grau porque o maior expoente ao qual a inc\u00f3gnita est\u00e1 submetida \u00e9 igual a 1 (ou seja, temos x\u00b9, abreviado como <em>x<\/em>, e n\u00e3o termos de graus superiores como x\u00b2 ou x\u00b3).<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"15:1-15:100;1544-1643\">A forma geral de uma equa\u00e7\u00e3o do 1\u00ba grau com uma inc\u00f3gnita no conjunto dos n\u00fameros reais \u00e9 dada por:<\/p>\n<blockquote class=\"ml-2 border-l-4 border-[hsl(var(--border-300)\/0.1)] pl-4 text-text-300\" data-sourcepos=\"17:1-17:17;1645-1661\">\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"17:3-17:17;1647-1661\"><strong>ax + b = 0<\/strong><\/p>\n<\/blockquote>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"19:1-19:6;1663-1668\">Onde:<\/p>\n<ul class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc flex flex-col gap-1 pl-8 mb-3 print:block print:space-y-1\" dir=\"ltr\" data-sourcepos=\"21:1-22:104;1670-1852\">\n<li class=\"font-claude-response-body whitespace-normal break-words pl-2\" data-sourcepos=\"21:1-21:79;1670-1748\"><strong>x<\/strong> representa a inc\u00f3gnita (o valor desconhecido que buscamos determinar).<\/li>\n<li class=\"font-claude-response-body whitespace-normal break-words pl-2\" data-sourcepos=\"22:1-22:104;1749-1852\"><strong>a<\/strong> e <strong>b<\/strong> s\u00e3o coeficientes reais conhecidos, com a condi\u00e7\u00e3o fundamental de exist\u00eancia: <strong>a \u2260 0<\/strong>.<\/li>\n<\/ul>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"24:1-24:409;1854-2262\">Sob a \u00f3tica do rigor conceitual, pense na igualdade como uma balan\u00e7a de dois pratos em equil\u00edbrio. O valor num\u00e9rico contido no primeiro membro (\u00e0 esquerda da igualdade) \u00e9 id\u00eantico ao do segundo membro (\u00e0 direita). O Princ\u00edpio de Equival\u00eancia das Equa\u00e7\u00f5es nos garante que qualquer opera\u00e7\u00e3o fundamental realizada em um dos membros deve ser obrigatoriamente efetuada no outro membro para preservar o equil\u00edbrio.<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"26:1-26:279;2264-2542\">Quando dizemos informalmente que um termo &#8220;passa para o outro lado trocando o sinal&#8221;, estamos, na verdade, aplicando o Princ\u00edpio Aditivo (somando o oposto sim\u00e9trico). Da mesma forma, aplicando o Princ\u00edpio Multiplicativo (multiplicando pelo inverso) em ambos os lados da equa\u00e7\u00e3o.<\/p>\n<h2 class=\"mt-3 -mb-1 text-[1.125rem] font-bold\" dir=\"ltr\" data-sourcepos=\"28:1-28:54;2544-2597\">Passo a passo para isolar o x com precis\u00e3o e rigor<\/h2>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"30:1-30:111;2599-2709\">Para determinar o conjunto solu\u00e7\u00e3o da equa\u00e7\u00e3o sem cometer erros operacionais, siga esta sequ\u00eancia estruturada:<\/p>\n<h3 class=\"mt-2 -mb-1 text-base font-bold\" dir=\"ltr\" data-sourcepos=\"32:1-32:48;2711-2758\">1. Elimine par\u00eanteses e fra\u00e7\u00f5es (se houver)<\/h3>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"34:1-34:298;2760-3057\">Caso existam par\u00eanteses, aplique a Propriedade Distributiva da multiplica\u00e7\u00e3o. Se houver termos fracion\u00e1rios com denominadores distintos, calcule o M\u00ednimo M\u00faltiplo Comum (MMC) de todos os denominadores presentes em ambos os membros para reescrever os termos sobre o mesmo denominador e elimin\u00e1-los.<\/p>\n<h3 class=\"mt-2 -mb-1 text-base font-bold\" dir=\"ltr\" data-sourcepos=\"36:1-36:41;3059-3099\">2. Aplique a transposi\u00e7\u00e3o dos termos<\/h3>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"38:1-38:247;3101-3347\">Agrupe todos os termos que cont\u00eam a inc\u00f3gnita <em>x<\/em> no primeiro membro e os termos independentes (apenas n\u00fameros) no segundo membro. Lembre-se: ao operar a transposi\u00e7\u00e3o de um termo para o membro oposto, inverta a opera\u00e7\u00e3o matem\u00e1tica correspondente.<\/p>\n<h3 class=\"mt-2 -mb-1 text-base font-bold\" dir=\"ltr\" data-sourcepos=\"40:1-40:36;3349-3384\">3. Reduza os termos semelhantes<\/h3>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"42:1-42:142;3386-3527\">Adicione ou subtraia os coeficientes das inc\u00f3gnitas no primeiro membro e simplifique os valores num\u00e9ricos no segundo membro, obtendo a forma:<\/p>\n<blockquote class=\"ml-2 border-l-4 border-[hsl(var(--border-300)\/0.1)] pl-4 text-text-300\" data-sourcepos=\"44:1-44:13;3529-3541\">\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"44:3-44:13;3531-3541\"><strong>ax = b<\/strong><\/p>\n<\/blockquote>\n<h3 class=\"mt-2 -mb-1 text-base font-bold\" dir=\"ltr\" data-sourcepos=\"46:1-46:38;3543-3580\">4. Determine o valor da inc\u00f3gnita<\/h3>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"48:1-48:64;3582-3645\">Divida ambos os membros pelo coeficiente <em>a<\/em> (desde que a \u2260 0):<\/p>\n<blockquote class=\"ml-2 border-l-4 border-[hsl(var(--border-300)\/0.1)] pl-4 text-text-300\" data-sourcepos=\"50:1-50:16;3647-3662\">\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"50:3-50:16;3649-3662\"><strong>x = b \/ a<\/strong><\/p>\n<\/blockquote>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"52:1-52:156;3664-3819\">Se o termo com <em>x<\/em> resultar em valor negativo (por exemplo, \u2013x = k), multiplique ambos os membros por \u20131 para obter o valor positivo correspondente de <em>x<\/em>.<\/p>\n<h2 class=\"mt-3 -mb-1 text-[1.125rem] font-bold\" dir=\"ltr\" data-sourcepos=\"54:1-54:49;3821-3869\">Tradu\u00e7\u00e3o de enunciados e pegadinhas cl\u00e1ssicas<\/h2>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"56:1-56:247;3871-4117\">Em exames oficiais, o desafio principal do candidato raramente reside no c\u00e1lculo alg\u00e9brico isolado, mas sim na modelagem do problema. A banca descreve uma situa\u00e7\u00e3o em linguagem natural e voc\u00ea precisa traduzi-la para a linguagem matem\u00e1tica formal.<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"58:1-58:80;4119-4198\">Confira a equival\u00eancia entre as express\u00f5es textuais e alg\u00e9bricas mais cobradas:<\/p>\n<div class=\"overflow-x-auto w-full px-2 mb-6 print:overflow-x-visible\" dir=\"ltr\" data-sourcepos=\"60:1-67:72;4200-4543\">\n<figure id=\"attachment_1727\" aria-describedby=\"caption-attachment-1727\" style=\"width: 1200px\" class=\"wp-caption alignnone\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-1727 size-full\" src=\"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/08\/do-texto-para-linguagem-algebrica.webp\" alt=\"Tradu\u00e7\u00e3o de enunciados e pegadinhas cl\u00e1ssicas\" width=\"1200\" height=\"628\" srcset=\"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/08\/do-texto-para-linguagem-algebrica.webp 1200w, https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/08\/do-texto-para-linguagem-algebrica-300x157.webp 300w, https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/08\/do-texto-para-linguagem-algebrica-1024x536.webp 1024w, https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/08\/do-texto-para-linguagem-algebrica-768x402.webp 768w\" sizes=\"auto, (max-width: 1200px) 100vw, 1200px\" \/><figcaption id=\"caption-attachment-1727\" class=\"wp-caption-text\">Tradu\u00e7\u00e3o de enunciados.<\/figcaption><\/figure>\n<\/div>\n<h3 class=\"mt-2 -mb-1 text-base font-bold\" dir=\"ltr\" data-sourcepos=\"69:1-69:38;4545-4582\">A armadilha do comando da quest\u00e3o<\/h3>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"71:1-71:375;4584-4958\">Assim como vimos no artigo sobre Regra de Tr\u00eas Simples, \u00e9 preciso aten\u00e7\u00e3o total ao comando final do enunciado. Muitas vezes voc\u00ea faz toda a \u00e1lgebra corretamente e encontra <em>x = 10<\/em>, mas o examinador n\u00e3o perguntou o valor de <em>x<\/em>, e sim o triplo desse valor (30) ou o valor somado a uma constante. Fique atento para n\u00e3o marcar a alternativa do valor intermedi\u00e1rio no gabarito.<\/p>\n<h2 class=\"mt-3 -mb-1 text-[1.125rem] font-bold\" dir=\"ltr\" data-sourcepos=\"73:1-73:21;4960-4980\">Como cai na prova<\/h2>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"75:1-75:169;4982-5150\">Para fixar bem a aplica\u00e7\u00e3o dos conceitos e observar como a modelagem de equa\u00e7\u00f5es \u00e9 cobrada em provas oficiais, analise a resolu\u00e7\u00e3o detalhada das duas quest\u00f5es a seguir:<\/p>\n<h3 class=\"mt-2 -mb-1 text-base font-bold\" dir=\"ltr\" data-sourcepos=\"77:1-77:23;5152-5174\">Quest\u00e3o 1 \u2014 VUNESP<\/h3>\n<blockquote class=\"ml-2 border-l-4 border-[hsl(var(--border-300)\/0.1)] pl-4 text-text-300\" data-sourcepos=\"79:1-79:98;5176-5273\">\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"79:3-79:98;5178-5273\"><strong>Banca:<\/strong> VUNESP \u00b7 <strong>\u00d3rg\u00e3o:<\/strong> TJ-SP \u00b7 <strong>Cargo:<\/strong> Escrevente T\u00e9cnico Judici\u00e1rio \u00b7 <strong>Ano:<\/strong> 2021<\/p>\n<\/blockquote>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"81:1-81:300;5275-5574\">Para a organiza\u00e7\u00e3o de um evento, foram compradas garrafas de suco de laranja e garrafas de suco de uva, em um total de 48 garrafas. Sabendo que o n\u00famero de garrafas de suco de laranja superava o n\u00famero de garrafas de suco de uva em 12 unidades, o n\u00famero de garrafas de suco de laranja compradas foi:<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"83:1-87:6;5576-5605\">A) 18 B) 24 C) 30 D) 32 E) 36<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"89:1-89:25;5607-5631\"><strong>Resolu\u00e7\u00e3o Comentada:<\/strong><\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"91:1-91:233;5633-5865\"><strong>1. Defini\u00e7\u00e3o das vari\u00e1veis:<\/strong> Vamos definir a quantidade de garrafas de suco de uva como <em>x<\/em>. Como o n\u00famero de garrafas de suco de laranja supera o de uva em 12 unidades, a quantidade de suco de laranja ser\u00e1 expressa por <em>x + 12<\/em>.<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"93:1-93:110;5867-5976\"><strong>2. Modelagem da Equa\u00e7\u00e3o do 1\u00ba Grau:<\/strong> A soma do total de garrafas de suco de laranja e de uva \u00e9 igual a 48:<\/p>\n<blockquote class=\"ml-2 border-l-4 border-[hsl(var(--border-300)\/0.1)] pl-4 text-text-300\" data-sourcepos=\"95:1-95:20;5978-5997\">\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"95:3-95:20;5980-5997\">(x + 12) + x = 48<\/p>\n<\/blockquote>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"97:1-97:80;5999-6078\"><strong>3. Resolu\u00e7\u00e3o alg\u00e9brica:<\/strong> Reduzindo os termos semelhantes no primeiro membro:<\/p>\n<blockquote class=\"ml-2 border-l-4 border-[hsl(var(--border-300)\/0.1)] pl-4 text-text-300\" data-sourcepos=\"99:1-99:15;6080-6094\">\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"99:3-99:15;6082-6094\">2x + 12 = 48<\/p>\n<\/blockquote>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"101:1-101:67;6096-6162\">Aplicando o princ\u00edpio aditivo (subtraindo 12 de ambos os membros):<\/p>\n<blockquote class=\"ml-2 border-l-4 border-[hsl(var(--border-300)\/0.1)] pl-4 text-text-300\" data-sourcepos=\"103:1-104:10;6164-6188\">\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"103:3-104:10;6166-6188\">2x = 48 \u2212 12 2x = 36<\/p>\n<\/blockquote>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"106:1-106:26;6190-6215\">Isolando a inc\u00f3gnita <em>x<\/em>:<\/p>\n<blockquote class=\"ml-2 border-l-4 border-[hsl(var(--border-300)\/0.1)] pl-4 text-text-300\" data-sourcepos=\"108:1-108:48;6217-6264\">\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"108:3-108:48;6219-6264\">x = 36 \/ 2 \u2192 x = 18 garrafas de suco de uva<\/p>\n<\/blockquote>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"110:1-110:120;6266-6385\"><strong>4. Verifica\u00e7\u00e3o do comando da quest\u00e3o:<\/strong> O enunciado solicita especificamente o n\u00famero de garrafas de suco de laranja:<\/p>\n<blockquote class=\"ml-2 border-l-4 border-[hsl(var(--border-300)\/0.1)] pl-4 text-text-300\" data-sourcepos=\"112:1-112:43;6387-6429\">\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"112:3-112:43;6389-6429\">Laranja = x + 12 = 18 + 12 = 30 garrafas<\/p>\n<\/blockquote>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"114:1-114:22;6431-6452\"><strong>Gabarito: Letra C<\/strong><\/p>\n<h3 class=\"mt-2 -mb-1 text-base font-bold\" dir=\"ltr\" data-sourcepos=\"116:1-116:20;6454-6473\">Quest\u00e3o 2 \u2014 FGV<\/h3>\n<blockquote class=\"ml-2 border-l-4 border-[hsl(var(--border-300)\/0.1)] pl-4 text-text-300\" data-sourcepos=\"118:1-118:76;6475-6550\">\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"118:3-118:76;6477-6550\"><strong>Banca:<\/strong> FGV \u00b7 <strong>\u00d3rg\u00e3o:<\/strong> IBGE \u00b7 <strong>Cargo:<\/strong> Recenseador \u00b7 <strong>Ano:<\/strong> 2017<\/p>\n<\/blockquote>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"120:1-120:296;6552-6847\">O n\u00famero de balas de menta que J\u00falia tinha era o dobro do n\u00famero de balas de morango. Ap\u00f3s dar 5 balas de cada um desses dois sabores para sua irm\u00e3, agora o n\u00famero de balas de menta que J\u00falia tem \u00e9 o triplo do n\u00famero de balas de morango. O n\u00famero total de balas que J\u00falia tinha inicialmente era:<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"122:1-126:6;6849-6878\">A) 42 B) 36 C) 30 D) 27 E) 24<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"128:1-128:25;6880-6904\"><strong>Resolu\u00e7\u00e3o Comentada:<\/strong><\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"130:1-130:211;6906-7116\"><strong>1. Defini\u00e7\u00e3o das vari\u00e1veis no estado inicial:<\/strong> Seja <em>x<\/em> a quantidade inicial de balas de morango. Como as de menta representavam o dobro, a quantidade inicial de menta era <em>2x<\/em>. O total inicial de balas era:<\/p>\n<blockquote class=\"ml-2 border-l-4 border-[hsl(var(--border-300)\/0.1)] pl-4 text-text-300\" data-sourcepos=\"132:1-132:14;7118-7131\">\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"132:3-132:14;7120-7131\">2x + x = 3x<\/p>\n<\/blockquote>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"134:1-134:57;7133-7189\"><strong>2. Modelagem ap\u00f3s a doa\u00e7\u00e3o de 5 balas de cada sabor:<\/strong><\/p>\n<ul class=\"[li_&amp;]:mb-0 [li_&amp;]:mt-1 [li_&amp;]:gap-1 [&amp;:not(:last-child)_ul]:pb-1 [&amp;:not(:last-child)_ol]:pb-1 list-disc flex flex-col gap-1 pl-8 mb-3 print:block print:space-y-1\" dir=\"ltr\" data-sourcepos=\"136:1-137:36;7191-7263\">\n<li class=\"font-claude-response-body whitespace-normal break-words pl-2\" data-sourcepos=\"136:1-136:37;7191-7227\">Quantidade atual de morango: x \u2212 5<\/li>\n<li class=\"font-claude-response-body whitespace-normal break-words pl-2\" data-sourcepos=\"137:1-137:36;7228-7263\">Quantidade atual de menta: 2x \u2212 5<\/li>\n<\/ul>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"139:1-139:101;7265-7365\">O enunciado afirma que a quantidade atual de menta \u00e9 igual ao triplo da quantidade atual de morango:<\/p>\n<blockquote class=\"ml-2 border-l-4 border-[hsl(var(--border-300)\/0.1)] pl-4 text-text-300\" data-sourcepos=\"141:1-141:23;7367-7389\">\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"141:3-141:23;7369-7389\">2x \u2212 5 = 3 \u00b7 (x \u2212 5)<\/p>\n<\/blockquote>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"143:1-143:84;7391-7474\"><strong>3. Resolu\u00e7\u00e3o alg\u00e9brica:<\/strong> Aplicando a propriedade distributiva no segundo membro:<\/p>\n<blockquote class=\"ml-2 border-l-4 border-[hsl(var(--border-300)\/0.1)] pl-4 text-text-300\" data-sourcepos=\"145:1-145:19;7476-7494\">\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"145:3-145:19;7478-7494\">2x \u2212 5 = 3x \u2212 15<\/p>\n<\/blockquote>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"147:1-147:87;7496-7582\">Agrupando os termos com a inc\u00f3gnita <em>x<\/em> no primeiro membro e as constantes no segundo:<\/p>\n<blockquote class=\"ml-2 border-l-4 border-[hsl(var(--border-300)\/0.1)] pl-4 text-text-300\" data-sourcepos=\"149:1-150:11;7584-7614\">\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"149:3-150:11;7586-7614\">2x \u2212 3x = \u221215 + 5 \u2212x = \u221210<\/p>\n<\/blockquote>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"152:1-152:39;7616-7654\">Multiplicando ambos os membros por \u22121:<\/p>\n<blockquote class=\"ml-2 border-l-4 border-[hsl(var(--border-300)\/0.1)] pl-4 text-text-300\" data-sourcepos=\"154:1-154:50;7656-7705\">\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"154:3-154:50;7658-7705\">x = 10 (quantidade inicial de balas de morango)<\/p>\n<\/blockquote>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"156:1-156:108;7707-7814\"><strong>4. C\u00e1lculo da pergunta final:<\/strong> A quest\u00e3o pede o n\u00famero total de balas que J\u00falia tinha inicialmente (3x):<\/p>\n<blockquote class=\"ml-2 border-l-4 border-[hsl(var(--border-300)\/0.1)] pl-4 text-text-300\" data-sourcepos=\"158:1-158:36;7816-7851\">\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"158:3-158:36;7818-7851\">Total Inicial = 3 \u00b7 10 = 30 balas<\/p>\n<\/blockquote>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"160:1-160:22;7853-7874\"><strong>Gabarito: Letra C<\/strong><\/p>\n<h2 class=\"mt-3 -mb-1 text-[1.125rem] font-bold\" dir=\"ltr\" data-sourcepos=\"162:1-162:23;7876-7898\">Resumo e dica final<\/h2>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"164:1-164:318;7900-8217\">Dominar a <strong>Equa\u00e7\u00e3o do 1\u00ba Grau<\/strong> \u00e9 garantir uma base s\u00f3lida para resolver a maioria das quest\u00f5es quantitativas em concursos p\u00fablicos. Lembre-se sempre de ler o enunciado com aten\u00e7\u00e3o, traduzir as informa\u00e7\u00f5es passo a passo e resolver as opera\u00e7\u00f5es com rigor absoluto em rela\u00e7\u00e3o aos sinais e ao comando final do problema.<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"166:1-166:245;8219-8463\">Mantenha uma rotina di\u00e1ria de resolu\u00e7\u00e3o de exerc\u00edcios de provas anteriores para automatizar o seu racioc\u00ednio e ganhar agilidade. Acompanhe mais materiais e dicas de estudo navegando no <a class=\"underline underline underline-offset-2 decoration-1 decoration-current\/40 hover:decoration-current focus:decoration-current\" href=\"https:\/\/www.aprovaconcursos.com.br\/blog\/\" rel=\"noopener noreferrer\" target=\"_blank\">Blog do Aprova<\/a>.<\/p>\n<p class=\"font-claude-response-body break-words whitespace-normal\" dir=\"ltr\" data-sourcepos=\"168:1-168:32;8465-8496\">Bons estudos e vamos que vamos!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Se voc\u00ea est\u00e1 firme na caminhada dos estudos para concursos p\u00fablicos, saiba que a Equa\u00e7\u00e3o do 1\u00ba Grau \u00e9 a linguagem essencial da Matem\u00e1tica e do Racioc\u00ednio L\u00f3gico. Ela n\u00e3o aparece apenas em quest\u00f5es diretas pedindo para resolver uma igualdade. Ela \u00e9 a ferramenta central utilizada pelas bancas para traduzir problemas de idades, fra\u00e7\u00f5es de [&hellip;]<\/p>\n","protected":false},"author":17,"featured_media":1728,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[8],"tags":[314,313],"estado":[],"class_list":["post-1722","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-professores","tag-equacao-do-1-grau","tag-equacao-do-1o-grau"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v28.0 (Yoast SEO v28.0) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>Aprova Concursos<\/title>\n<meta name=\"description\" content=\"Domine a Equa\u00e7\u00e3o do 1\u00ba Grau para concursos! Aprenda o passo a passo, como traduzir enunciados e evite pegadinhas com quest\u00f5es comentadas.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.aprovaconcursos.com.br\/blog\/equacao-do-1-grau\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Aprova Concursos\" \/>\n<meta property=\"og:description\" content=\"Domine a Equa\u00e7\u00e3o do 1\u00ba Grau para concursos! Aprenda o passo a passo, como traduzir enunciados e evite pegadinhas com quest\u00f5es comentadas.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/www.aprovaconcursos.com.br\/blog\/equacao-do-1-grau\/\" \/>\n<meta property=\"og:site_name\" content=\"Aprova Concursos: Blog de Estudos e Carreiras\" \/>\n<meta property=\"article:published_time\" content=\"2026-08-13T12:00:30+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2026-08-13T13:07:32+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/08\/equacao-do-1-grau-para-concursos.webp\" \/>\n\t<meta property=\"og:image:width\" content=\"1200\" \/>\n\t<meta property=\"og:image:height\" content=\"628\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/webp\" \/>\n<meta name=\"author\" content=\"Prof\u00ba Andr\u00e9 Luis Tatarin\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:title\" content=\"Aprova Concursos\" \/>\n<meta name=\"twitter:label1\" content=\"Escrito por\" \/>\n\t<meta name=\"twitter:data1\" content=\"Prof\u00ba Andr\u00e9 Luis Tatarin\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. tempo de leitura\" \/>\n\t<meta name=\"twitter:data2\" content=\"8 minutos\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\\\/\\\/schema.org\",\"@graph\":[{\"@type\":[\"Article\",\"BlogPosting\"],\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/equacao-do-1-grau\\\/#article\",\"isPartOf\":{\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/equacao-do-1-grau\\\/\"},\"author\":{\"name\":\"Prof\u00ba Andr\u00e9 Luis Tatarin\",\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/#\\\/schema\\\/person\\\/7672acc19679fe9642c0bba4f44f5160\"},\"headline\":\"Equa\u00e7\u00e3o do 1\u00ba Grau: como isolar o &#8220;x&#8221; sem errar na prova\",\"datePublished\":\"2026-08-13T12:00:30+00:00\",\"dateModified\":\"2026-08-13T13:07:32+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/equacao-do-1-grau\\\/\"},\"wordCount\":1400,\"publisher\":{\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/#organization\"},\"image\":{\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/equacao-do-1-grau\\\/#primaryimage\"},\"thumbnailUrl\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/wp-content\\\/uploads\\\/2026\\\/08\\\/equacao-do-1-grau-para-concursos.webp\",\"keywords\":[\"Equa\u00e7\u00e3o do 1 Grau\",\"Equa\u00e7\u00e3o do 1\u00ba Grau\"],\"articleSection\":[\"Professores\"],\"inLanguage\":\"pt-BR\"},{\"@type\":\"WebPage\",\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/equacao-do-1-grau\\\/\",\"url\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/equacao-do-1-grau\\\/\",\"name\":\"Equa\u00e7\u00e3o do 1\u00ba Grau: como isolar o \\\"x\\\" sem errar na prova\",\"isPartOf\":{\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/#website\"},\"primaryImageOfPage\":{\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/equacao-do-1-grau\\\/#primaryimage\"},\"image\":{\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/equacao-do-1-grau\\\/#primaryimage\"},\"thumbnailUrl\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/wp-content\\\/uploads\\\/2026\\\/08\\\/equacao-do-1-grau-para-concursos.webp\",\"datePublished\":\"2026-08-13T12:00:30+00:00\",\"dateModified\":\"2026-08-13T13:07:32+00:00\",\"description\":\"Domine a Equa\u00e7\u00e3o do 1\u00ba Grau para concursos! Aprenda o passo a passo, como traduzir enunciados e evite pegadinhas com quest\u00f5es comentadas.\",\"breadcrumb\":{\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/equacao-do-1-grau\\\/#breadcrumb\"},\"inLanguage\":\"pt-BR\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/equacao-do-1-grau\\\/\"]}]},{\"@type\":\"ImageObject\",\"inLanguage\":\"pt-BR\",\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/equacao-do-1-grau\\\/#primaryimage\",\"url\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/wp-content\\\/uploads\\\/2026\\\/08\\\/equacao-do-1-grau-para-concursos.webp\",\"contentUrl\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/wp-content\\\/uploads\\\/2026\\\/08\\\/equacao-do-1-grau-para-concursos.webp\",\"width\":1200,\"height\":628,\"caption\":\"Equa\u00e7\u00e3o do 1\u00ba Grau: como n\u00e3o errar na prova\"},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/equacao-do-1-grau\\\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Equa\u00e7\u00e3o do 1\u00ba Grau: como isolar o &#8220;x&#8221; sem errar na prova\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/#website\",\"url\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/\",\"name\":\"Aprova Concursos - Blog\",\"description\":\"Guias, m\u00e9todos de estudo e an\u00e1lises t\u00e1ticas para sua aprova\u00e7\u00e3o em concursos p\u00fablicos.\",\"publisher\":{\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/#organization\"},\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/?s={search_term_string}\"},\"query-input\":{\"@type\":\"PropertyValueSpecification\",\"valueRequired\":true,\"valueName\":\"search_term_string\"}}],\"inLanguage\":\"pt-BR\"},{\"@type\":\"Organization\",\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/#organization\",\"name\":\"Aprova Concursos\",\"url\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/\",\"logo\":{\"@type\":\"ImageObject\",\"inLanguage\":\"pt-BR\",\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/#\\\/schema\\\/logo\\\/image\\\/\",\"url\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/wp-content\\\/uploads\\\/2026\\\/05\\\/cropped-logo-aprova-3.png\",\"contentUrl\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/wp-content\\\/uploads\\\/2026\\\/05\\\/cropped-logo-aprova-3.png\",\"width\":1416,\"height\":538,\"caption\":\"Aprova Concursos\"},\"image\":{\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/#\\\/schema\\\/logo\\\/image\\\/\"},\"sameAs\":[\"https:\\\/\\\/www.youtube.com\\\/@aprovaconcursos\",\"https:\\\/\\\/www.tiktok.com\\\/@aprovaconcursosoficial\"]},{\"@type\":\"Person\",\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/#\\\/schema\\\/person\\\/7672acc19679fe9642c0bba4f44f5160\",\"name\":\"Prof\u00ba Andr\u00e9 Luis Tatarin\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"pt-BR\",\"@id\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/wp-content\\\/uploads\\\/2026\\\/07\\\/Professor-Andre-Tatarin-Aprova-150x150.webp\",\"url\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/wp-content\\\/uploads\\\/2026\\\/07\\\/Professor-Andre-Tatarin-Aprova-150x150.webp\",\"contentUrl\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/wp-content\\\/uploads\\\/2026\\\/07\\\/Professor-Andre-Tatarin-Aprova-150x150.webp\",\"caption\":\"Prof\u00ba Andr\u00e9 Luis Tatarin\"},\"description\":\"Licenciado e Mestre em Matem\u00e1tica pela Universidade Federal do Paran\u00e1 (UFPR). Possui 23 anos de s\u00f3lida experi\u00eancia docente na educa\u00e7\u00e3o b\u00e1sica, ensino superior e cursos preparat\u00f3rios, com atua\u00e7\u00e3o nas redes p\u00fablica e privada e em renomadas institui\u00e7\u00f5es de ensino. \u00c9 autor e editor de materiais did\u00e1ticos, criador do canal Matem\u00e1tica Linda e professor especialista em Matem\u00e1tica e Racioc\u00ednio L\u00f3gico no Aprova Concursos.\",\"sameAs\":[\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/\"],\"url\":\"https:\\\/\\\/www.aprovaconcursos.com.br\\\/blog\\\/autor\\\/prof-andre-tatarin\\\/\"}]}<\/script>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Aprova Concursos","description":"Domine a Equa\u00e7\u00e3o do 1\u00ba Grau para concursos! Aprenda o passo a passo, como traduzir enunciados e evite pegadinhas com quest\u00f5es comentadas.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/www.aprovaconcursos.com.br\/blog\/equacao-do-1-grau\/","og_locale":"pt_BR","og_type":"article","og_title":"Aprova Concursos","og_description":"Domine a Equa\u00e7\u00e3o do 1\u00ba Grau para concursos! Aprenda o passo a passo, como traduzir enunciados e evite pegadinhas com quest\u00f5es comentadas.","og_url":"https:\/\/www.aprovaconcursos.com.br\/blog\/equacao-do-1-grau\/","og_site_name":"Aprova Concursos: Blog de Estudos e Carreiras","article_published_time":"2026-08-13T12:00:30+00:00","article_modified_time":"2026-08-13T13:07:32+00:00","og_image":[{"width":1200,"height":628,"url":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/08\/equacao-do-1-grau-para-concursos.webp","type":"image\/webp"}],"author":"Prof\u00ba Andr\u00e9 Luis Tatarin","twitter_card":"summary_large_image","twitter_title":"Aprova Concursos","twitter_misc":{"Escrito por":"Prof\u00ba Andr\u00e9 Luis Tatarin","Est. tempo de leitura":"8 minutos"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":["Article","BlogPosting"],"@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/equacao-do-1-grau\/#article","isPartOf":{"@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/equacao-do-1-grau\/"},"author":{"name":"Prof\u00ba Andr\u00e9 Luis Tatarin","@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/#\/schema\/person\/7672acc19679fe9642c0bba4f44f5160"},"headline":"Equa\u00e7\u00e3o do 1\u00ba Grau: como isolar o &#8220;x&#8221; sem errar na prova","datePublished":"2026-08-13T12:00:30+00:00","dateModified":"2026-08-13T13:07:32+00:00","mainEntityOfPage":{"@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/equacao-do-1-grau\/"},"wordCount":1400,"publisher":{"@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/#organization"},"image":{"@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/equacao-do-1-grau\/#primaryimage"},"thumbnailUrl":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/08\/equacao-do-1-grau-para-concursos.webp","keywords":["Equa\u00e7\u00e3o do 1 Grau","Equa\u00e7\u00e3o do 1\u00ba Grau"],"articleSection":["Professores"],"inLanguage":"pt-BR"},{"@type":"WebPage","@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/equacao-do-1-grau\/","url":"https:\/\/www.aprovaconcursos.com.br\/blog\/equacao-do-1-grau\/","name":"Equa\u00e7\u00e3o do 1\u00ba Grau: como isolar o \"x\" sem errar na prova","isPartOf":{"@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/#website"},"primaryImageOfPage":{"@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/equacao-do-1-grau\/#primaryimage"},"image":{"@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/equacao-do-1-grau\/#primaryimage"},"thumbnailUrl":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/08\/equacao-do-1-grau-para-concursos.webp","datePublished":"2026-08-13T12:00:30+00:00","dateModified":"2026-08-13T13:07:32+00:00","description":"Domine a Equa\u00e7\u00e3o do 1\u00ba Grau para concursos! Aprenda o passo a passo, como traduzir enunciados e evite pegadinhas com quest\u00f5es comentadas.","breadcrumb":{"@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/equacao-do-1-grau\/#breadcrumb"},"inLanguage":"pt-BR","potentialAction":[{"@type":"ReadAction","target":["https:\/\/www.aprovaconcursos.com.br\/blog\/equacao-do-1-grau\/"]}]},{"@type":"ImageObject","inLanguage":"pt-BR","@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/equacao-do-1-grau\/#primaryimage","url":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/08\/equacao-do-1-grau-para-concursos.webp","contentUrl":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/08\/equacao-do-1-grau-para-concursos.webp","width":1200,"height":628,"caption":"Equa\u00e7\u00e3o do 1\u00ba Grau: como n\u00e3o errar na prova"},{"@type":"BreadcrumbList","@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/equacao-do-1-grau\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/www.aprovaconcursos.com.br\/blog\/"},{"@type":"ListItem","position":2,"name":"Equa\u00e7\u00e3o do 1\u00ba Grau: como isolar o &#8220;x&#8221; sem errar na prova"}]},{"@type":"WebSite","@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/#website","url":"https:\/\/www.aprovaconcursos.com.br\/blog\/","name":"Aprova Concursos - Blog","description":"Guias, m\u00e9todos de estudo e an\u00e1lises t\u00e1ticas para sua aprova\u00e7\u00e3o em concursos p\u00fablicos.","publisher":{"@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/#organization"},"potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/www.aprovaconcursos.com.br\/blog\/?s={search_term_string}"},"query-input":{"@type":"PropertyValueSpecification","valueRequired":true,"valueName":"search_term_string"}}],"inLanguage":"pt-BR"},{"@type":"Organization","@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/#organization","name":"Aprova Concursos","url":"https:\/\/www.aprovaconcursos.com.br\/blog\/","logo":{"@type":"ImageObject","inLanguage":"pt-BR","@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/#\/schema\/logo\/image\/","url":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/05\/cropped-logo-aprova-3.png","contentUrl":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/05\/cropped-logo-aprova-3.png","width":1416,"height":538,"caption":"Aprova Concursos"},"image":{"@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/#\/schema\/logo\/image\/"},"sameAs":["https:\/\/www.youtube.com\/@aprovaconcursos","https:\/\/www.tiktok.com\/@aprovaconcursosoficial"]},{"@type":"Person","@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/#\/schema\/person\/7672acc19679fe9642c0bba4f44f5160","name":"Prof\u00ba Andr\u00e9 Luis Tatarin","image":{"@type":"ImageObject","inLanguage":"pt-BR","@id":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/07\/Professor-Andre-Tatarin-Aprova-150x150.webp","url":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/07\/Professor-Andre-Tatarin-Aprova-150x150.webp","contentUrl":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-content\/uploads\/2026\/07\/Professor-Andre-Tatarin-Aprova-150x150.webp","caption":"Prof\u00ba Andr\u00e9 Luis Tatarin"},"description":"Licenciado e Mestre em Matem\u00e1tica pela Universidade Federal do Paran\u00e1 (UFPR). Possui 23 anos de s\u00f3lida experi\u00eancia docente na educa\u00e7\u00e3o b\u00e1sica, ensino superior e cursos preparat\u00f3rios, com atua\u00e7\u00e3o nas redes p\u00fablica e privada e em renomadas institui\u00e7\u00f5es de ensino. \u00c9 autor e editor de materiais did\u00e1ticos, criador do canal Matem\u00e1tica Linda e professor especialista em Matem\u00e1tica e Racioc\u00ednio L\u00f3gico no Aprova Concursos.","sameAs":["https:\/\/www.aprovaconcursos.com.br\/"],"url":"https:\/\/www.aprovaconcursos.com.br\/blog\/autor\/prof-andre-tatarin\/"}]}},"_links":{"self":[{"href":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-json\/wp\/v2\/posts\/1722","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-json\/wp\/v2\/users\/17"}],"replies":[{"embeddable":true,"href":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-json\/wp\/v2\/comments?post=1722"}],"version-history":[{"count":1,"href":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-json\/wp\/v2\/posts\/1722\/revisions"}],"predecessor-version":[{"id":1729,"href":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-json\/wp\/v2\/posts\/1722\/revisions\/1729"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-json\/wp\/v2\/media\/1728"}],"wp:attachment":[{"href":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-json\/wp\/v2\/media?parent=1722"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-json\/wp\/v2\/categories?post=1722"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-json\/wp\/v2\/tags?post=1722"},{"taxonomy":"estado","embeddable":true,"href":"https:\/\/www.aprovaconcursos.com.br\/blog\/wp-json\/wp\/v2\/estado?post=1722"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}